Find LCM of two or three numbers | C-Program

LCM of two or three numbers:

 

 

Tips:-

1. Find the highest number among the two or three numbers through as you like.
2. Remember that LCM will not be less than the highest number.
3. Now, store it in a variable say x, divide the x with all the others.
4. If the remainder is zero, than x is the LCM.
5. Else increase the value of x by one and check it again.
6. Do it until every number divides x and gives remainder zero.
7. You can use a infinite while loop for it and break when it get satisfied.
8. At last you will get x as the LCM.               

NOTE: Ignore the name of variables used in the program below, just understand how it works and customize it in a way you feel comfortable.

Code:-

#include<stdio.h>
int lcm2(int x, int y)
{  int minval;
    minval=(x>y)?x:y;
    while(1)
   {
     if(minval%x==0&&minval%y==0)
     {
      printf("LCM of %d and %d is %d",x,y,minval);
      break;
     }
     minval++;
   }
 }
int lcm3(int x, int y, int z)
 {  int minval;
    minval=(x>y)?((x>z)?x:z):((y>z)?y:z);
    while(1)
    {
      if(minval%x==0&&minval%y==0&&minval%z==0)
      {
       printf("LCM of %d , %d and %d is %d",x,y,z,minval);
       break;
      }
      minval++;
    }
 }
void main()
{ int lcm2(int x, int y);
  int lcm3(int x, int y, int z);
  int x,y,z,var;
  nab : printf("    L C M \n\n1. LCM of two numbers.\n2. LCM of three numbers.\n99. Exit\n    Enter 1 or 2 or 99\n");
  scanf("%d",&var);
  while(1)
  {
  if(var==1)
  { printf("\nEnter two numbers :\n");
    scanf("%d %d",&x,&y);
    lcm2(x,y);
    break;
  }
  if(var==2)
  { printf("\nEnter three numbers :\n");
    scanf("%d %d %d",&x,&y,&z);
    lcm3(x,y,z);
    break;
  }
  if(var==99)
  { break; }
  else
  goto nab;
  }
}

Output:

LCM of two numbers:

LCM of three numbers :

 

 If you have any doubt to understand the program, feel free to comment down blow.

 Thank You.